From: Brian McGahan (bmcgahan@internetworkexpert.com)
Date: Sun May 23 2004 - 11:38:05 GMT-3
Ahmed,
5Mbps is your target output rate, and 7.5Mbps is your effective
maximum transmission rate (access-rate). The values are derived as
follows:
Bc = CIR * Tc/1000
Bc = 5000000 * 32/1000
Bc = 160000
Be = (AR-CIR) * Tc/1000
Be = (7500000-5000000) * 32/1000
Be = 80000
HTH,
Brian McGahan, CCIE #8593
bmcgahan@internetworkexpert.com
Internetwork Expert, Inc.
http://www.InternetworkExpert.com
Toll Free: 877-224-8987 x 705
Outside US: 775-826-4344 x 705
> -----Original Message-----
> From: nobody@groupstudy.com [mailto:nobody@groupstudy.com] On Behalf
Of
> Ahmed Mustafa
> Sent: Sunday, May 23, 2004 2:53 AM
> To: ccielab@groupstudy.com
> Subject: Shaping
>
> If the task's requirment says that
>
> CIR is 5MB on an OC-3 link, and provider has agreed to allow you to
burst
> up
> to 7.5MB for a maximum of 32ms.
>
> Is the term "BURST UP TO" means that this becomes a virtual
access-rate.
>
> To calculate Be = (AR- CIR) * 32/1000
>
> What value will replace AR the actual target rate which is OC-3 Link
or
> 7.5MB
> which is "BURST UP TO"
>
> Regards,
>
> Ahmed
>
>
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