From: John Matijevic (matijevi@bellsouth.net)
Date: Sat Mar 27 2004 - 13:09:30 GMT-3
Hello,
I believe you need to set the variance = 3. Basically you look at the
two values from the eigrp topology: 156160 and 386560. If you divide
386560/156169= 2.4 rounded up you get 3.
http://www.cisco.com/en/US/tech/tk365/tk207/technologies_tech_note09186a
008009437d.shtml
Sincerely,
John
-----Original Message-----
From: nobody@groupstudy.com [mailto:nobody@groupstudy.com] On Behalf Of
Serran
Sent: Saturday, March 27, 2004 10:58 AM
To: ccielab@groupstudy.com
Subject: RE: EIGRP - Variance
You need to take a closer look at what the toplogy table is telling
you..
386560 < (variance 2)* 156160 is not true.
hth
Serran.
-----Original Message-----
From: nobody@groupstudy.com [mailto:nobody@groupstudy.com]On Behalf Of k
c
Sent: Sunday, 28 March 2004 1:22 AM
To: ccielab@groupstudy.com
Subject: EIGRP - Variance
Dear All,
How to calculate the variance used in eigrp to allow the routing table
showing two possible routes using "sh eigrp topology" result? I have
tried
useing variance = 2, but fail.
5.0.0.0/32 is subnetted, 1 subnets
D 5.5.5.5 [90/156160] via 142.1.65.5, 00:00:04, FastEthernet2/0
P 5.5.5.5/32, 1 successors, FD is 156160
via 142.1.65.5 (156160/128256), FastEthernet2/0
via 142.1.56.5 (386560/128256), FastEthernet0/0
Thanks,
JWong
%21~'^!B6<:q!B$p,P,P...
.v:)9aAn 1!$_3sC4
http://ringtone.yahoo.com.hk/
This archive was generated by hypermail 2.1.4 : Thu Apr 01 2004 - 08:15:49 GMT-3