From: Michael Davis (miked@netrus.net)
Date: Sun Oct 19 2003 - 14:43:19 GMT-3
You are right that Be is 4000. However, in order for Tc to equal 1, Bc must
be 12000. Tc=Bc/CIR, 1=12000/12000.
In your solution, Tc = .125sec= 1500/12000. So your peak is 352,000/sec
when it should be 16000.
HTH,
Mike
#7303
----- Original Message -----
From: "k c" <jwongccie@yahoo.com.hk>
To: <ccielab@groupstudy.com>
Sent: Sunday, October 19, 2003 3:17 AM
Subject: Bc and Be Calculation
> Question on R6:
> - CIR for the PVC connecting to router 14 should be 12kbps
> - If BECNs are received, R6 should throttle back to 50% of the CIR
configured for the PVC that the BECNs were received
> - The peak rate should be 33% higher than the CIR for each PVC
>
> I don' t know how to calculate the Bc and Be based on the above info.
Bc/CIR = Tc. Does it assign Tc to 1 sec such that BC=12000 bps x 1 sec 8 =
1500 Byte. For Be, in 1 sec interval, Be=12000 x 1 x 33/100 = 4000. Do I
correct?
>
>
> Ans:
> map-class frame-relay 12kbs
> frame-relay cir 12000
> frame-relay bc 1500
> frame-relay be 4000
> frame-relay mincir 6000
> frame-relay adaptive-shaping becn
>
>
>
> (b-S$H*:)/9B!B6C%@(N$H!B9J(#...
> .v:)9aAn 1!$_3sC4
> http://ringtone.yahoo.com.hk/
>
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