From: Brian McGahan (bmcgahan@internetworkexpert.com)
Date: Sun Oct 19 2003 - 17:44:00 GMT-3
Bc = CIR * Tc/1000
Be = (AR-CIR) * Tc/1000
In your case, the CIR is 12000, and the AR is 15960 (12000 *
1.33). For a CIR of 12000, the default Tc will be 125ms. Therefore
your calculation should be as follows:
Bc = 12000 * 125/1000
Bc = 1500
Be = 15960-12000 * 125/1000
Be = 495
For more info:
http://www.internetworkexpert.com/resources/01700368.htm
HTH,
Brian McGahan, CCIE #8593
bmcgahan@internetworkexpert.com
Internetwork Expert, Inc.
http://www.InternetworkExpert.com
Toll Free: 877-224-8987
Direct: 708-362-1418 (Outside the US and Canada)
> -----Original Message-----
> From: nobody@groupstudy.com [mailto:nobody@groupstudy.com] On Behalf
Of k
> c
> Sent: Sunday, October 19, 2003 2:18 AM
> To: ccielab@groupstudy.com
> Subject: Bc and Be Calculation
>
> Question on R6:
> - CIR for the PVC connecting to router 14 should be 12kbps
> - If BECNs are received, R6 should throttle back to 50% of the CIR
> configured for the PVC that the BECNs were received
> - The peak rate should be 33% higher than the CIR for each PVC
>
> I don' t know how to calculate the Bc and Be based on the above info.
> Bc/CIR = Tc. Does it assign Tc to 1 sec such that BC=12000 bps x 1 sec
8 =
> 1500 Byte. For Be, in 1 sec interval, Be=12000 x 1 x 33/100 = 4000. Do
I
> correct?
>
>
> Ans:
> map-class frame-relay 12kbs
> frame-relay cir 12000
> frame-relay bc 1500
> frame-relay be 4000
> frame-relay mincir 6000
> frame-relay adaptive-shaping becn
>
>
>
> (b-S$H*:)/9B!B6C%@(N$H!B9J(#...
> .v:)9aAn 1!$_3sC4
> http://ringtone.yahoo.com.hk/
>
>
This archive was generated by hypermail 2.1.4 : Mon Nov 24 2003 - 07:53:05 GMT-3