From: Brian McGahan (bmcgahan@internetworkexpert.com)
Date: Wed Aug 27 2003 - 21:21:27 GMT-3
Nat,
That will match a little more than you're looking for.
Something like this would work:
_123(_.+)?_456_
HTH,
Brian McGahan, CCIE #8593
bmcgahan@internetworkexpert.com
Internetwork Expert, Inc.
http://www.InternetworkExpert.com
Toll Free: 877-334-8987
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-----Original Message-----
From: nobody@groupstudy.com [mailto:nobody@groupstudy.com] On Behalf Of
Nathaly Landry
Sent: Wednesday, August 27, 2003 6:37 PM
To: 'Chepuri Roshan'; 'Ram Shummoogum'
Cc: ccielab@groupstudy.com
Subject: RE: regular expression
Cleaning up my folder, did not see an answer for that one, I
think that the reg expression is:
Reg exp to only accept routes that have transitted thru AS 123 AND AS
456
^((.+_)*123(_.+)*_456(_.+)*)$|((.+_)*123(_.+)*_456(_.+)*$)
Any idea?
Nat
-----Original Message-----
From: nobody@groupstudy.com [mailto:nobody@groupstudy.com] On Behalf Of
Chepuri Roshan
Sent: Thursday, February 20, 2003 11:55 PM
To: Ram Shummoogum
Cc: ccielab@groupstudy.com
Subject: Re:
Try _[1,4][2,5][3,6]_
At 10:34 PM 2/20/2003 -0500, Ram Shummoogum wrote:
>Hi ALL:
>
>
>I need some help on this BGP regular expression.
>
>
>Make a router only accept routes that has transit AS 123 and AS 456.
>The keyword here is "and" and not or.
>
>
>Ex: {34 5 6 456 7 99 123 88}
> {45 123 89 456 7}
>
>
>
>
>
>I know "OR" is | but what is AND.
>
>
>
>
>
>Thanks for your help
>
>
>RAM
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