From: wsqccie@hotnail.com
Date: Mon Apr 07 2003 - 14:27:34 GMT-3
maxir=cir(1+be/bc)
bc=cie*tc , normal tc=125ms
----- Original Message -----
From: "Rick" <ccie_2003@hotmail.com>
To: <ccielab@groupstudy.com>; "Scott M. Livingston" <scottl@sprinthosting.net>
Sent: Monday, April 07, 2003 10:37 AM
Subject: Re: QOS question on Bc with CAR
> This what I found too in the cisco press Qos book, but it never matches up
> with any of their answers..
>
> Thanks,
> Rick
> ----- Original Message -----
> From: "Scott M. Livingston" <scottl@sprinthosting.net>
> To: "'Rick'" <ccie_2003@hotmail.com>; <ccielab@groupstudy.com>
> Sent: Sunday, April 06, 2003 10:25 PM
> Subject: RE: QOS question on Bc with CAR
>
>
> > W/ CAR I use:
> >
> > Bc = configured rate / 8 * 1.5
> > Be = Bc * 2
> >
> > thanks,
> > scott
> >
> > -----Original Message-----
> > From: nobody@groupstudy.com [mailto:nobody@groupstudy.com] On Behalf Of
> > Rick
> > Sent: Sunday, April 06, 2003 8:22 PM
> > To: ccielab@groupstudy.com
> > Subject: QOS question on Bc with CAR
> >
> > Can soneone please explain a simple way to figure out the Bc with CAR. I
> > have
> > been simply dividing the access rate by 8. I know this can't be right
> > because
> > my numbers never match the book. Any help would be greatly appreciated.
> >
> > Thanks,
> > Rick
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