From: ccie_studying (ccie_studying@hotmail.com)
Date: Tue Mar 25 2003 - 17:36:51 GMT-3
I think if only summary to one network, it should be:
164.24.32.0 with wildcard 15.7.15.255 or subnet mask 240.248.240.0
----- Original Message -----
From: "Scott M. Livingston" <scottl@sprinthosting.net>
To: <ccielab@groupstudy.com>
Sent: Tuesday, March 25, 2003 11:26 AM
Subject: 1 aggregated ACL
> This was posted on another board so I wanted to check the answer that
> was given. It happens to be the same answer I came up with. Also, if
> someone has any other teasers maybe you can post them. I am using the
> formula Tim Fletcher taught those of us that were doing it another way
> (my wrong way :)).
>
> 165.24.45.0
> 167.24.47.0
> 175.28.65.0
>
>
> Answer:
> 165.24.1.0 mask 10.4.110.255
>
> thank you,
> scott
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