From: Scott Morris (swm@emanon.com)
Date: Wed Mar 12 2003 - 10:16:54 GMT-3
The wildcard bits come from the DIFFERENT values, which gives you the
idea of the "I don't care" bits.
199 = 11000111
204 = 11001100
---------------
Diff= 00001011
THAT in binary is 8 + 2 + 1 = 11.
Scott
-----Original Message-----
From: nobody@groupstudy.com [mailto:nobody@groupstudy.com] On Behalf Of
Pratt, Jeremy
Sent: Tuesday, March 11, 2003 8:14 PM
To: 'Jim Brown'; Scott Morris; Voss, David; ccielab@groupstudy.com
Subject: RE: ACL Tips and Tricks
I got the 199, 204 and match bits but where the the wildcard bits come
from?
-----Original Message-----
From: Jim Brown [mailto:Jim.Brown@caselogic.com]
Sent: Tuesday, March 11, 2003 2:46 PM
To: Scott Morris; Voss, David; ccielab@groupstudy.com
Subject: RE: ACL Tips and Tricks
access-list 1 permit 196.95.60.0 11.0.0.255
199 = 11000111
204 = 11001100
--------------
196 = 11000100 exact match bits
11 = 00001011 wildcard bits
This solution will include the 205 and 207 networks in addition to the
199 and 204 networks.
This is the BEST answer IMHO.
-----Original Message-----
From: Scott Morris [mailto:swm@emanon.com]
Sent: Tuesday, March 11, 2003 12:34 PM
To: 'Voss, David'; ccielab@groupstudy.com
Subject: RE: ACL Tips and Tricks
199 = 11000111
204 = 11001100
There are 3 bits of difference between the two, so it is impossible to
summarize them in one statement without including extraneous routes.
Enjoy!
Scott
-----Original Message-----
From: nobody@groupstudy.com [mailto:nobody@groupstudy.com] On Behalf Of
Voss, David
Sent: Tuesday, March 11, 2003 12:49 PM
To: ccielab@groupstudy.com
Subject: ACL Tips and Tricks
Permit the following subnets in an ACL with only 1 command... and deny
all other subnets.... I don't believe this can be done with 1 command.
Maybe someone can give it a shot?
204.95.160.0/24
199.95.160.0/24
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