From: CCIE FUN (ccieexam2002@yahoo.com)
Date: Wed Mar 12 2003 - 02:12:06 GMT-3
yep
that's what i calculated
196.95.160.0 11.0.0.255
--- Jim Brown <Jim.Brown@caselogic.com> wrote:
> access-list 1 permit 196.95.60.0 11.0.0.255
>
> 199 = 11000111
> 204 = 11001100
> --------------
> 196 = 11000100 exact match bits
> 11 = 00001011 wildcard bits
>
> This solution will include the 205 and 207 networks
> in addition to the
> 199 and 204 networks.
>
> This is the BEST answer IMHO.
>
> -----Original Message-----
> From: Scott Morris [mailto:swm@emanon.com]
> Sent: Tuesday, March 11, 2003 12:34 PM
> To: 'Voss, David'; ccielab@groupstudy.com
> Subject: RE: ACL Tips and Tricks
>
>
> 199 = 11000111
> 204 = 11001100
>
> There are 3 bits of difference between the two, so
> it is impossible to
> summarize them in one statement without including
> extraneous routes.
>
> Enjoy!
>
> Scott
>
> -----Original Message-----
> From: nobody@groupstudy.com
> [mailto:nobody@groupstudy.com] On Behalf Of
> Voss, David
> Sent: Tuesday, March 11, 2003 12:49 PM
> To: ccielab@groupstudy.com
> Subject: ACL Tips and Tricks
>
>
> Permit the following subnets in an ACL with only 1
> command... and deny
> all other subnets.... I don't believe this can be
> done with 1 command.
> Maybe someone can give it a shot?
>
> 204.95.160.0/24
> 199.95.160.0/24
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