From: Herve Bruyere (hbruyere@cisco.com)
Date: Mon Mar 10 2003 - 07:05:18 GMT-3
OK, so:
1 = 0 0 0 0 0 0 0 1
3 = 0 0 0 0 0 0 1 1
5 = 0 0 0 0 0 1 0 1
147 = 1 0 0 1 0 0 1 1
----------------------
X 0 0 X 0 X X 1 = 10010111 = 151
and the result is 201.201.1.0 0.0.151.0
regards
rv
eric wrote:
> Sorry guys,
> I should have been more clear
> ie.....
> allow
> 201.201.1.0, 201.201.3.0, 201.201.5.0, 201.201.147.0
> do this with a minimum of lines.
> now I know that 201.201.1.0 0.0.151.0 works. ( It also allows others which
> is fine ).
> What I am trying to get my mind around is how to do it on the fly so to
> speak. with enough time and a couple of routers I can muddle my way thru.
>
> I understand the care and dont care bits part, " Its in relation to what"
> that I am confused with. I know its not that hard and yet..........
>
> regards,
>
> ~e
>
> -----Original Message-----
> From: nobody@groupstudy.com [mailto:nobody@groupstudy.com]On Behalf Of
> eric
> Sent: Sunday, March 09, 2003 4:55 PM
> To: Ccielab
> Subject: inverse masks
>
>
> Hello,
>
> Does anybody have a formula or a shortcut that will help me get these.
> I dont know why I cant seem to get my mind around it. I just end up
> confusing myself with the ORed results. It cant be as hard and as confusing
> as I am making it out to be.
>
> Regards,
>
> ~e
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