From: Sam Munzani (sam@munzani.com)
Date: Wed Mar 05 2003 - 20:15:32 GMT-3
Totally understand that. And that's why we get input and output queue drop
counters incremented on the router.
Pretty much my argument is,
If the traffic is linear, T1 can run at 100% utilization without any
problems.
For burst, you can't do much about it either it's at 100% or 80%. You will
alway miss some packets because of burst and buffers getting full.
In short, either at 60%, 80% or 100% the performance of your apps would be
same if same kind of burst pattern exists on each utilization. Am I wrong?
Sam
> On Wednesday, March 05, 2003, Sam Munzani wrote:
>
> -----Original Message-----
> SM> My understanding was a full T1 is 1540000 bps. This is full duplex.
That
> SM> means up to that speed if router keeps putting bits to the serial
> SM> interface's output bucket, the line will pick it up and forward it to
the
> SM> other end. When the router starts buffering data more than that rate,
the
> SM> serial interface buffers will be full and hence start dropping bits to
the
> SM> bit bucket. I didn't see any issue until the bucket gets full. The
drops are
> SM> added to the "output queue drop" counters on "sh int" command. My
logic is,
> SM> when the T1 is at 80% utilization, the line can still forward every
single
> SM> bit of it so nothing will go to the queue drop. Is my thinking wrong?
>
> Yes, you are assuming that utilization is linear. Traffic is
> always bursty.
>
>
> --
> Thanks
> syv@911networks.com
> When the network has to work
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