From: André Bersvendsen (an-bersv@xxxxxxxxx)
Date: Mon Aug 12 2002 - 05:41:54 GMT-3
Bc = 1/8 of CIR only if Tc=125mS (this is the normal/default value for Tc).
Bc = CIR*Tc
Example:
Bc=?
CIR=64000
Tc=0.125
Bc=64000*0.125
Bc=8000
Bc=8Kbps
CIR do not have anything with port speed (also called access rate (AR))
to do. It must be lower than the access rate.
And now LAB14:
On page 382 the following information is given:
port speed (JPL)=1.544 Mbps
CIR=32Kbps.
port speed (nasa_houston)=64Kbps
In FRTS you must configure MinCIR=32Kbps.
And Bc is calculated from CIR in FRTS.
>Can someone please clarify something for me? When
>cisco says that bc = 1/8 of cir, that basically means
>that 8/CIR=Bc . If this is so are they refering to CIR
>being the provider CIR or the CIR that is used in TS ,
>such as Port speed? I am just trying to figure out how
>Karl Solie arrived at this values on lab 14 in the
>preparation volume 1.
>Thanks
>
>
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