From: Jason Sinclair (sinclairj@xxxxxxxxxxxxxxx)
Date: Wed Dec 05 2001 - 02:18:19 GMT-3
It would depend on how the question was worded and what the intent was as
they are all correct, however they all do slightly different things, but
address your question,
Jason Sinclair
Manager, Network Support Group
POWERTEL
Ground Level, 55 Clarence Street,
SYDNEY NSW 2000
AUSTRALIA
office: + 61 2 8264 3820
mobile: + 61 2 416 105 858
* sinclairj@powertel.com.au
-----Original Message-----
From: Albert Lu [mailto:albert_ccie@yahoo.com]
Sent: Wednesday, 5 December 2001 13:06
To: 'Gregory W. Posey Jr.'
Cc: ccielab@groupstudy.com
Subject: RE: BGP Regular Expression Quizz
Greg,
I've tried it with ^7474.*13606$ and ^7474_.*_13606$ and
^7474 .* 13606$
They all work. What is the most correct solution?
Albert
-----Original Message-----
From: Gregory W. Posey Jr. [mailto:gposey@uaes.org]
Sent: Wednesday, December 05, 2001 11:22 AM
To: Albert Lu; ccielab@groupstudy.com
Subject: RE: BGP Regular Expression Quizz
I would think the appropriate regular expression would be...
^7474 .* 13606$
Since .* is the same as all paths (according to Halabi)
Thank you,
Greg Posey Jr.
CCIE #7981
CCNP - Security Specialist
Cisco Voice Access Specialist
M.S. EE
-----Original Message-----
From: nobody@groupstudy.com [mailto:nobody@groupstudy.com]On
Behalf Of
Albert Lu
Sent: Tuesday, December 04, 2001 6:54 PM
To: ccielab@groupstudy.com
Subject: BGP Regular Expression Quizz
Quick quizz on how well you guys know your Regular
Expressions.
How can match a route that has originated from AS 13606 and
ending at AS
7474
An example would be
Network Next Hop Metric LocPrf Weight
Path
* i209.37.145.0 216.14.195.13 1000 0
7474 701 7018
13606 i
My best attempt is:
^7474(_[0-9]+_)13606$
It doesn't work
Thanks
Albert
This archive was generated by hypermail 2.1.4 : Thu Jun 13 2002 - 10:32:38 GMT-3