Re: Bootcamp lab 18: Broadcast Supression

From: LabStudy (labstudy@xxxxxxxxx)
Date: Thu Feb 22 2001 - 01:47:02 GMT-3


   
under ospf protocol,cost=100000000/bw,in doyle book,56k line cost is 1785,so bw
 is 56000,it isn't 56*1024.
----- Original Message -----
From: "Peter Puczko" <ppuczko@excite.com>
To: <ccielab@groupstudy.com>
Sent: Friday, February 16, 2001 12:43 AM
Subject: RE: Bootcamp lab 18: Broadcast Supression

> 3MB is actually 3,145,728 bytes not 3,072,000
> I didn't wake up completely. Sorry.
>
> Peter
>
>
> On Thu, 15 Feb 2001 11:30:37 -0500, Foster, Kristopher wrote:
>
> > I believe in the telcom world a megabit is 1,000,000 bits
> >
> > Kris,
> >
> > -----Original Message-----
> > From: Hardin Les - SMTP [mailto:hardinl@bah.com]
> > Sent: Thursday, February 15, 2001 11:00 AM
> > To: Derek Buelna; ccielab@groupstudy.com
> > Subject: Re: Bootcamp lab 18: Broadcast Supression
> >
> >
> >
> > FYI.
> >
> > Actually, 3Mbps = 3,072,000 bits per sec.
> >
> > Les
> >
> > At 02:37 AM 2/15/2001 -0800, Derek Buelna wrote:
> > >Hi,
> > >
> > >I was thinking that if I was asked to configure this I'd probably do it
> > >one way but they would have wanted it the other way.
> > >
> > >In lab 18 I believe it says to limit broadcasts on a port, on the
> > >catalyst, to 3Mb/s.
> > >
> > >Ok, so I read that the percentage of bandwidth method is more accurate
> > >and also hardware based but the answer uses the per packet method.
> > >
> > >I'm taking it that 3,000,000 bits/s / 8 = 375,000 bytes/s. I'm
> > >assuming that an average packet size of 1024 would make for an average
> > >throughput of 366.21 of these kinds of packets/s.
> > >
> > >Am I understanding this correctly?
> > >
> > >Wouldn't it be easier to just say 30%, since it's a 10,000,000 bits/s
> > >link?
> > >
> > >set port broadcast 2/9 367
> > >set port broadcast 2/9 30%
> > >
> > >Thanks,
> > >
> > >-Derek
> > >
> > >
> > >
> > >



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