From: Marc Russell (mrussell@xxxxxxxxxxxxxx)
Date: Sun Feb 18 2001 - 02:03:44 GMT-3
Below is an example.
This would filter all of the odd routes. This only uses a standard
access list.
access-list 3 deny 192.168.1.0 0.0.254.255
access-list 3 permit any
Marc Russell
CCIE Boot Camp
www.ccbootcamp.com
-----Original Message-----
From: Chuck Larrieu [mailto:chuck@cl.cncdsl.com]
Sent: Saturday, February 17, 2001 11:46 PM
To: Nobody Important; Ccielab
Subject: RE: Lost Email on Access List
Actually, you should be able to figure this one out quite easily.
An odd number has the last bit to the right set at 1 ( one )
An even number has the last bit to the right set at 0 ( zero )
5 = odd = 0000 0101
4 = even = 0000 0100
this is always the case.
HTH
Chuck
-----Original Message-----
From: nobody@groupstudy.com [mailto:nobody@groupstudy.com] On Behalf
Of
Nobody Important
Sent: Saturday, February 17, 2001 8:27 PM
To: Ccielab
Subject: Lost Email on Access List
Hi Gang,
I have been trying to find the thread on the archives where somebody
gave an
example/challenge on filtering out even and odd networks using extended
access list. I lost my copy when I cleaned out my mailbox. I figured I
have time to fool around with this but I couldn't find the example.
Can somebody email me one of the a copy or tell me what was the title so
I
can find it in the archives.
Thanks...
stanford
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