Re: frame relay traffic shaping

From: kongck (kongck@xxxxxxxxxxxxxx)
Date: Wed Oct 20 1999 - 05:25:27 GMT-3


   

--- Mike Wang <mike_wang51@hotmail.com> wrote:
> Hi,
>
> I am sure you guys read the frame relay traffic
> shaping samples on CCO. I
> found something need to discuss with you regarding
> be calculation.
>
> The first example is cir 64000, bc 8000, mincir
> 16000, be 0. I understand
> be=port speed - cir =0

Peak rate=cir(1+Be/Bc)

> However, the second example is cir 64000, mincir
> 16000, bc 8000, be 72000. I
> do not understand this one: be should = port speed
> (128000)-cir (64000)
> =64000. The answer 72000 is obviously added bc. So
> my question is: should
> be include bc? My answer is be should be 64000.

if the port speed is 128000,i think the Be=Bc=8000

> Thanks,
> Mike
>
>



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