From: Ron Trunk (rtrunk@xxxxxxxxxxxxx)
Date: Mon Aug 09 1999 - 10:21:52 GMT-3
Eng Wee,
Cip = (p * Cot) / (1-p)
Cip = byte count of IP queue
Cot = total byte count of all other queues
p = bandwidth percentage (as decimal)
If you have four queues and want 80% bandwidth on one (default queue size is
1500)
Cip = (.8 * 4500) / (1 - .8)
Cip = 3600 / .2
Cip = 18000
Ron
-----Original Message-----
From: Chuah Eng Wee <chuahew@cyberway.com.sg>
To: ccielab@groupstudy.com <ccielab@groupstudy.com>
Date: Monday, August 09, 1999 5:58 AM
Subject: custom queueing- byte count
>Hi..
>
>I understand that we can use the byte count parameter
>in custom queueing to indirectly specify which protocol
>use more bandwidth.
>
>Caslow's book give a fomula and an example, but it is only for 50%
>utilisation.
>
>For e.g, if I want to have ip traffic occupying 80% of the bandwidth,
>20% for the rest. How do I calculate the byte count
>to get the desired result ??
>
>Thanks
>Eng Wee
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