Tc is used indirectly to determine your Bc. You must know this formula:
CIR=Bc/Tc => 512kb/s=Bc/.05s => Bc=512kb/s*.05s=25600b
In your example sounds like you can have an additional burst capability up
to the access rate of 1.536Mb/s. Therefore you have
1536kb/s-512kb/s=1.024Mb/s of bursting capability remaining per 1s. You
however need to determine how much per Tc. To determine this you perform
similar calculation as above (AR-CIR)=Be/Tc =>
(1.536k-512k)=1024kb/s=Be/.05s => Be=51200b
On Sat, Dec 11, 2010 at 12:19 PM, Manouchehr Omari <manouchehr1979_at_gmail.com
> wrote:
> Hello All,
>
> Anyone can explain below?
>
> CIR = 512Kbps
> Tc=50ms
>
>
> *(25600 + Be)= 1536000*50/1000 and therefore Be = 51200.*
>
>
> Blogs and organic groups at http://www.ccie.net
>
> _______________________________________________________________________
> Subscription information may be found at:
> http://www.groupstudy.com/list/CCIELab.html
Blogs and organic groups at http://www.ccie.net
Received on Sat Dec 11 2010 - 15:29:53 ART
This archive was generated by hypermail 2.2.0 : Sat Jan 01 2011 - 09:37:49 ART