Hi All,
Was doing a EIGRP lab & came across following observation in the EIGRP
topologu table.
as per the output there are two paths to 155.1.79.0 255.255.255.0,
But my problem is FD is 2816 via 155.1.67.7, second route via 155.1.146.1 is
having a AD of 3072, But as per my undestanding if the AD of the feasible
successor is > the FD successor it can not be there in the topology table,
Pls correct me if I am wrong.
sh ip eigrp topo 155.1.79.0 255.255.255.0
IP-EIGRP (AS 100): Topology entry for 155.1.79.0/24
State is Passive, Query origin flag is 1, 1 Successor(s), FD is 2816
Routing Descriptor Blocks:
155.1.67.7 (FastEthernet0/0.67), from 155.1.67.7, Send flag is 0x0
Composite metric is (2816/256), Route is Internal
Vector metric:
Minimum bandwidth is 100000 Kbit
Total delay is 110 microseconds
Reliability is 255/255
Load is 1/255
Minimum MTU is 1500
Hop count is 1
155.1.146.1 (FastEthernet0/0.146), from 155.1.146.1, Send flag is 0x0
Composite metric is (5632/3072), Route is Internal
Vector metric:
Minimum bandwidth is 2048 Kbit
Total delay is 220 microseconds
Reliability is 255/255
Load is 1/255
Minimum MTU is 1500
Hop count is 3
Thanks
Sara
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Received on Sun Jul 18 2010 - 02:21:22 ART
This archive was generated by hypermail 2.2.0 : Sun Aug 01 2010 - 19:19:14 ART