Re: broadcast question

From: Scott Morris <smorris_at_ine.com>
Date: Tue, 02 Mar 2010 15:29:55 -0500

 Now, perhaps I'm over thinking this (and Ive already deleted the
original, so can't go back to look at what it was asking for)....

Helper address:

1 incoming --> 4 separate helper addresses to local broadcast on 4
separate networks.

Broadcast-multicast conversion:

1 incoming --> 1 multicast stream/address that happens to go OUT 4
separate interfaces

Unless we get into the nuances of joins or not, and assuming that I WANT
the traffic to go out all four interfaces, is the end result not going to
be the same either way?B One incoming packet = sent out four separate
interfaces.

*shrug*B I'll let you all tell me where I misread the part about
conserving bandwidth versus everyone on four /26 subnets must get it.

Scott

Carlos G Mendioroz wrote:

  Hmm,
  if he puts 4 helpers on the wan if, then only one wan packet on the wan
  will replicate 4 lan broadcasts. I thought the point is conserving wan
  bw. What am I missing ?
  
  On the other side, mcast helper is right on target, if you want to enter
  mcast world :)
  
  -Carlos
  
  Marko Milivojevic @ 2/03/2010 16:03 -0300 dixit:

    On Tue, Mar 2, 2010 at 18:56, Scott Morris <smorris_at_ine.com> wrote:

      B ip helper-address and ip forward-protocol to change the port information
      used? B Just have multiple helpers on the receiving interface. B (Tell 'em
      to use the broadcast of the receiving interface)

    This would work, but it would fail to concerve bandwidth, as traffic
    would be replicated N times - once for each helper address... No
    points for you ;-)
    
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Received on Tue Mar 02 2010 - 15:29:55 ART

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