Now, perhaps I'm over thinking this (and Ive already deleted the
original, so can't go back to look at what it was asking for)....
Helper address:
1 incoming --> 4 separate helper addresses to local broadcast on 4
separate networks.
Broadcast-multicast conversion:
1 incoming --> 1 multicast stream/address that happens to go OUT 4
separate interfaces
Unless we get into the nuances of joins or not, and assuming that I WANT
the traffic to go out all four interfaces, is the end result not going to
be the same either way?B One incoming packet = sent out four separate
interfaces.
*shrug*B I'll let you all tell me where I misread the part about
conserving bandwidth versus everyone on four /26 subnets must get it.
Scott
Carlos G Mendioroz wrote:
Hmm,
if he puts 4 helpers on the wan if, then only one wan packet on the wan
will replicate 4 lan broadcasts. I thought the point is conserving wan
bw. What am I missing ?
On the other side, mcast helper is right on target, if you want to enter
mcast world :)
-Carlos
Marko Milivojevic @ 2/03/2010 16:03 -0300 dixit:
On Tue, Mar 2, 2010 at 18:56, Scott Morris <smorris_at_ine.com> wrote:
B ip helper-address and ip forward-protocol to change the port information
used? B Just have multiple helpers on the receiving interface. B (Tell 'em
to use the broadcast of the receiving interface)
This would work, but it would fail to concerve bandwidth, as traffic
would be replicated N times - once for each helper address... No
points for you ;-)
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Received on Tue Mar 02 2010 - 15:29:55 ART
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