Re: BGP conditional adv??

Hi Ivan,
From the question,

- if both nets 1.0.0.0 and 2.0.0.0 are up, R1 should advertise them both
- if 1.0.0.0/8 is DOWN, R1 should not advertise 2.0.0.0/8 to R3
- if 2.0.0.0/8 is DOWN, R1 should only advertise net 1.0.0.0/8 to R3

network 2.0.0.0/8 is dependent on 1.0.0.0/8. (second requirement).
1st and third requirements are the default behavior of the BGP process.

Hence the solution only focuses on the second requirement.

HTH,

On 2/24/10, Ivan Hrvatska <ivanzghr_at_gmail.com> wrote:
> Hi experts,
>
> I have some difficulties to catch this scenario with BGP conditional adv:
>
> R1-----------R2
> |
> |
> R3
>
> R1 has lo0 1.1.1.1/8, R2 has Lo0 2.2.2.2/8 and R3 has also Lo0
> 3.3.3.3/8. All RTs are in same AS and all of them advertise their
> loopbacks.
> Task is next:
> - if both nets 1.0.0.0 and 2.0.0.0 are up, R1 should advertise them both
> - if 1.0.0.0/8 is DOWN, R1 should not advertise 2.0.0.0/8 to R3
> - if 2.0.0.0/8 is DOWN, R1 should only advertise net 1.0.0.0/8 to R3
>
> Solution on R1:
> acl 1 permit 1.0.0.0 0.255.255.255
> acl 2 permit 2.0.0.0 0.255.255.255
>
> route-map ADV per 10
> match ip add 2
> route-map EXIST per 10
> match ip add 1
>
> router bgp 100
> neighbor R3 adv-map ADV exist-map EXIST
>
> So, from my point of view this task should do next:
> - if 1.0.0.0/8 is UP (2.0.0.0/8 can also be UP) advertise 2.0.0.0/8 to
> R3 (task asks you to NOT advertise)
> - if 1.0.0.0/8 is DOWN (2.0.0.0/8 can also be DOWN), do not advertise
> anything
>
> This solution is correct, but I don't get the logic?
>
>
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-- 
Best Regards,
Tolulope.
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