Re: Spanning-tree root port selection

Hi Guarav,

  Thanks for the response.Actually the below mentioned is true for all,but
when all those tied,which may be in the case where the topology in which hub
is in between and the non-root bridge is having 2 connections to it.In that
scenario,I am understanding that the local port id would be choosed as tie
breaker.If that is wrong,kindly correct me again.

Thanks for the help

Regards
Anantha Subramanian Natarajan

On Tue, Sep 15, 2009 at 1:36 PM, GAURAV MADAN <gauravmadan1177_at_gmail.com>wrote:

> Small error ...
>
> Correct one is
>
> Lowest BID
> Lowest root path cost
> Lowest sender Bridge Id
> Lowest sender Port Id
>
> HTH
> Gaurav Madan
> CCIE
>
> On Tue, Sep 15, 2009 at 11:58 PM, Anantha Subramanian Natarajan
> <anantha.natarajan_at_gravitant.com> wrote:
> > Hi All,
> >
> > When I went through LAN Switching Book,I understood the below(Please
> > correct me,If I am wrong)
> >
> > In the below scenario(Same Hub)
> >
> > SW1(Root Bridge) ---------Hub --------- SW2
> > Hub ----------SW2
> >
> > When SW2 tries to calculate its root port to the root bridge,by default
> all
> > the parameters(Path cost,sender bridge-id,port ID information SW1) all
> > ties,the SW2 uses it *local port ID* for the tie breaker. Is my
> > understanding right ? If so,when a question comes to describe a root port
> > selection ,should I need to mention this also like as below
> >
> > 1)Highest Root path cost
> > 2)Lowest sender bridge-id
> > 3) Lowest sender Bridge port ID
> > 4)* Lowest local port ID ,if all the above Tie*
> > **
> > Kindly correct me if I am wrong.
> >
> > Thank you very much
> >
> > Regards
> > Anantha Subramanian Natarajan
> >
> >
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Received on Tue Sep 15 2009 - 13:54:08 ART