To answer your question about IPv4, from RFC791 (IP)
"Every internet module must be able to forward a datagram of 68
octets without further fragmentation. This is because an internet
header may be up to 60 octets, and the minimum fragment is 8 octets.
Every internet destination must be able to receive a datagram of 576
octets either in one piece or in fragments to be reassembled."
On Thu, Aug 27, 2009 at 2:04 AM, Anantha Subramanian Natarajan <
anantha.natarajan_at_gravitant.com> wrote:
> Hi All,
>
> When I was going through the Doc CD for IPv6,I read about the "Minimum
> Link MTU is 1280 octets in IPv6".Even when referred the RFC 2460 (IPv6
> specification),it highlights the same.I am just curious about the
> significance of that number "1280 octets".How that is derived ?.Even I
> didn't know,what is the significance of the number 68 octets,which is
> minimum MTU size for Ipv4 .
>
> Any clarification is really appreciated.
>
> Thanks for the help
>
> Regards
> Anantha Subramanian Natarajan
>
>
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-- Regards, Joe Astorino - CCIE #24347 R&S Technical Instructor - IPexpert, Inc. Cell: +1.586.212.6107 Fax: +1.810.454.0130 Mailto: jastorino_at_ipexpert.com Blogs and organic groups at http://www.ccie.netReceived on Thu Aug 27 2009 - 02:29:56 ART
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