From: Ravi Singh (way2ccie@googlemail.com)
Date: Tue Mar 10 2009 - 08:57:56 ARST
Hi Marish,
Your diagram is not very clear. Is it some specific vendor lab you are
working on ? A better diagram would certainly help . Also remember the
bandwidth that you have to consider while calculating the metric from Router
A to Router B should be the lowest bandwidth value in the path from Router A
to Router B. Check your interfaces for any non default bandwidth values.
Look at the physical topology again carefully. I doubt, there is something
very basic that you are missing here.
HTH,
Ravi
On Tue, Mar 10, 2009 at 6:25 AM, marish shah <contactmarish@gmail.com>wrote:
> Hi Experts,
>
> Yesterday I was facing problem with eigrp lab.problem is reladed
> to FD (fesible distance) AD (advertise distance)
>
> ok Here is my senario
>
>
> Serial 1/3 155.1.13.3 155.1.13.1 Serial 1/0
> Fa0/0 155.1.146.1 155.1.146.6 Fa0/0.146
>
>
> R3------------------------------------------------------R1------------------------------------------------------------------------R6
>
> |
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> |Fa0/0
> 155.1.37.3
> |
>
> |
> 155.1.67.6 Fa0/0.67 |
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> | 155.1.37.7 Fa
> 1/3 155.1.67.7 Vlan
> 67 |
>
>
> |----------------------------------------------------------SW1---------------------------------------------------------------------|
>
> R1 fastethernet 0/0 is conectd with R6 Fastethernet 0/0.146
> R1 Serial 1/0 is conected with R3 Serial 1/3
> R3 fastethernet0/0 is conected with SW1 fastethernet 1/3
> R6 fastethernet 0/0.67 is conected with SW fastethernet 1/6
>
> Now I enable eigrp 100 on all routers.
>
> After runing eigrp 100 I try to calculate FD and AD my traget is interface
> between R3 & SW1 (155.1.37.0) I'm on router 1
>
> Here is sh ip eigrp topology on R1
>
> R1#sh ip eigrp topology
>
> P 155.1.37.0/24, 1 successors, FD is 286720
> via 155.1.146.6 (286720/284160), FastEthernet0/0 ------primary path
> via 155.1.13.3 (2195456/281600), Serial1/1 ------- Backup path
> here u see I have two paths to reach 155.1.37.0 so now decision on FD I'm
> get lowest FD ( 286720) from 155.1.146.6 so this my primary path.
> On this point every thing is OK I calculate my AD ( 281600) the result is
> same.But when I try to calculate my FD on router 1 my mind stuck.AS I know
> for FD first we take our AD , second we take our distance ( R1 to R6) then
> plus both and we get our FD.But its not work.
>
> On R1 MY FD is 286720 for calculate my distance to R6
>
>
> Rack1R1#sh interfaces fastEthernet 0/0
>
> BW 100000 Kbit, DLY 100 usec,
>
> 10^7/BW + DELAY x 256
>
> 10^7= 10000000
> 10000000/100000 = 100 + 10 = 110 X 256 = 28160 R1 distane to R6
>
> Now 28160 + 284160 = 312320 but as u see in topology table FD is 286720
> .................
> So how can I calculate my FD ?
>
>
> your suggestion is really helpful to me.
>
> Regards,
> Thanks.
>
>
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