From: Kelvin Yeo (kelvinyeo24@yahoo.com.sg)
Date: Sat Dec 13 2008 - 16:10:16 ARST
I am abit confused about the usage whether to use '0' or '255' as the last
octet. What scenario should either come into use?
Rdgs,
KY
-----Original Message-----
From: nobody@groupstudy.com [mailto:nobody@groupstudy.com] On Behalf Of John
Edom
Sent: 13 December 2008 23:00
To: Ryan DeBerry
Cc: Cisco certification
Subject: Re: ACL - Single Satement
Yes in that sense you are right but if i am using this acl in
distribution-list to match networks/prefixs i am thinking in that way...
because normal i have seen this kind of acls in route filtering.
Regards
On Sat, Dec 13, 2008 at 6:46 PM, Ryan DeBerry <rdeberry@gmail.com> wrote:
> If that were the case how many hosts are you gonna have on those networks?
>
> NONE.
>
> Make sense?
>
>
>
> On Sat, Dec 13, 2008 at 9:38 AM, John Edom <jedom123@gmail.com> wrote:
>
>> hi
>> Ryan/Sachin thanks for link and explaination. I am clear about 3 octate
>> now just tell me what about 4 octate because we are matching bit by bit
so
>> since in last octate all 0's are match it should be 0 in wildcard rather
>> then 255?
>>
>> Regards
>>
>>
>> On Sat, Dec 13, 2008 at 6:31 PM, Ryan DeBerry <rdeberry@gmail.com> wrote:
>>
>>>
>>>
http://blog.internetworkexpert.com/2007/12/26/q-how-do-i-compute-complex-wil
dcard-masks-for-access-lists/
>>>
>>>
>>> On Sat, Dec 13, 2008 at 9:31 AM, John Edom <jedom123@gmail.com> wrote:
>>>
>>>> Hi,
>>>>
>>>> Do anyone have some complex examples for batter understanding?
>>>>
>>>> Regards
>>>>
>>>>
>>>> On Sat, Dec 13, 2008 at 6:28 PM, John Edom <jedom123@gmail.com> wrote:
>>>>
>>>>> hi,
>>>>>
>>>>> i think wildcard will be 0.0.11.0 because in forth octet all networks
>>>>> have zeros so all match means 0.
>>>>>
>>>>> Third Octate
>>>>> 0100
>>>>> 0101
>>>>> 0110
>>>>> 0111
>>>>> 1100
>>>>> 1101
>>>>> 1110
>>>>> 1111
>>>>> --------
>>>>> 1011 - wildcard that is 11
>>>>>
>>>>> Correct me if i am wrong.......
>>>>>
>>>>> Regards
>>>>>
>>>>>
>>>>> On Sat, Dec 13, 2008 at 6:09 PM, Ryan DeBerry
<rdeberry@gmail.com>wrote:
>>>>>
>>>>>> I think it should be
>>>>>>
>>>>>> 192.168.4.0 0.0.11.255
>>>>>>
>>>>>> Third octet has last 4 in common
>>>>>>
>>>>>> 8-4-2-1
>>>>>>
>>>>>> 4 is always on so wild card mask it would be off.
>>>>>>
>>>>>> 8+2+1=11
>>>>>>
>>>>>> On Sat, Dec 13, 2008 at 7:42 AM, John Edom <jedom123@gmail.com>wrote:
>>>>>>
>>>>>>> Hi,
>>>>>>>
>>>>>>> can we write these all network in single ACL line
>>>>>>>
>>>>>>> 192.168.4.0
>>>>>>> 192.168.5.0
>>>>>>> 192.168.6.0
>>>>>>> 192.168.7.0
>>>>>>>
>>>>>>> 192.168.12.0
>>>>>>> 192.168.13.0
>>>>>>> 192.168.14.0
>>>>>>> 192.168.15.0
>>>>>>>
>>>>>>> Regards
>>>>>>>
>>>>>>>
>>>>>>> Blogs and organic groups at http://www.ccie.net
>>>>>>>
>>>>>>>
>>>>>>>
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