From: John Edom (jedom123@gmail.com)
Date: Sat Dec 13 2008 - 12:28:31 ARST
hi,
i think wildcard will be 0.0.11.0 because in forth octet all networks have
zeros so all match means 0.
Third Octate
0100
0101
0110
0111
1100
1101
1110
1111
--------
1011 - wildcard that is 11
Correct me if i am wrong.......
Regards
On Sat, Dec 13, 2008 at 6:09 PM, Ryan DeBerry <rdeberry@gmail.com> wrote:
> I think it should be
>
> 192.168.4.0 0.0.11.255
>
> Third octet has last 4 in common
>
> 8-4-2-1
>
> 4 is always on so wild card mask it would be off.
>
> 8+2+1=11
>
> On Sat, Dec 13, 2008 at 7:42 AM, John Edom <jedom123@gmail.com> wrote:
>
>> Hi,
>>
>> can we write these all network in single ACL line
>>
>> 192.168.4.0
>> 192.168.5.0
>> 192.168.6.0
>> 192.168.7.0
>>
>> 192.168.12.0
>> 192.168.13.0
>> 192.168.14.0
>> 192.168.15.0
>>
>> Regards
>>
>>
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>>
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