From: Ryan DeBerry (rdeberry@gmail.com)
Date: Sat Dec 13 2008 - 12:09:31 ARST
I think it should be
192.168.4.0 0.0.11.255
Third octet has last 4 in common
8-4-2-1
4 is always on so wild card mask it would be off.
8+2+1=11
On Sat, Dec 13, 2008 at 7:42 AM, John Edom <jedom123@gmail.com> wrote:
> Hi,
>
> can we write these all network in single ACL line
>
> 192.168.4.0
> 192.168.5.0
> 192.168.6.0
> 192.168.7.0
>
> 192.168.12.0
> 192.168.13.0
> 192.168.14.0
> 192.168.15.0
>
> Regards
>
>
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