From: Scott Morris (smorris@internetworkexpert.com)
Date: Wed Oct 22 2008 - 22:27:14 ARST
You'd have to spell them out. (the long and ugly method!)
GREP/Unix actually gives you the ability to specify number of occurrances
like (65000){1,7} which would look for "65000" occuring between 1 and 7
times.
IOS doesn't allow that at this point in time.
In case you're bored, JUNOS does. :)
HTH,
Scott Morris, CCIE4 #4713, JNCIE-M #153, JNCIS-ER, CISSP, et al.
CCSI/JNCI-M/JNCI-ER
Senior CCIE Instructor
smorris@internetworkexpert.com
Knowledge is power.
Power corrupts.
Study hard and be Eeeeviiiil......
-----Original Message-----
From: nobody@groupstudy.com [mailto:nobody@groupstudy.com] On Behalf Of
Hobbs
Sent: Wednesday, October 22, 2008 1:12 PM
To: Cisco certification
Subject: BGP regexp - how to find x number or more occurrences of an AS in
the AS path
Suppose I wanted to find all routes that have the same AS number in a row 8
or more times...is this possible using regexp?
The 8 could be any number (just not 0 or 1 which can use + or ?), I just
can't think of way to do 5 or more, 6 or more, etc...
thanks,
Blogs and organic groups at http://www.ccie.net
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