From: George Roman (georgeroman@gmail.com)
Date: Fri Jun 20 2008 - 10:43:46 ART
By default redistribution is a 2 step process.
Let's say you have RIP->OSPF
1. All rip routes (those with R in your routing table) are getting
redistributed into OSPF
2. The connected interfaces that are covered by rip "network" command are
getting into OSPF
If you are creating a manual route-map to redistribute connected into OSPF
for example, you are breaking the process nr 2. and you have to manually
"repair" it.
George
On Fri, Jun 20, 2008 at 2:50 PM, sathappan sathappan <
sathappan2003@gmail.com> wrote:
> Hi GS,
>
>
> In a router with RIP and ospf routing protocols, interface Loopback 0 is
> redistributed into ospf and connected interfaces like s1/0, s1/2, s1/3 are
> in ospf and int fa0/0 and fa0/1 are in rip.
>
>
> Upon mutual redistribution between rip and ospf, we match the loopback0 in
> a
> route-map and redistribute into ospf. But as per a LAB solution all the
> connected interfaces advertised in ospf are being redistributed manually
> into the rip via a route-map.
>
> why this is necessary? Please give us some explanations.
>
>
>
> regards
>
> sathappan
>
>
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