From: Scott Morris (swm@emanon.com)
Date: Thu Feb 28 2008 - 16:24:36 ARST
Honorable? You're making me sound old. :)
-----Original Message-----
From: nobody@groupstudy.com [mailto:nobody@groupstudy.com] On Behalf Of Greg
Wendel
Sent: Thursday, February 28, 2008 12:48 PM
To: abdul muhammed
Cc: Cisco certification
Subject: Re: need help on ipv6
To add to what the honorable Scott Morris wrote,
Write out the first bits in binary
hex 00 is binary 0000 0000
if you invert(change) the 7th bit 0 from a 0 to a 1 you get
bit number 1234 5678
beginning 0000.0000 = 00
changed value 0000 0010 = 02
as you can see we changed the 7th bit from a 0 to a 1 . This causes the
value of the first number to change from 0000 to 0010 - 0010 in binary = 2
in hex
Does this make sense?
On Thu, Feb 28, 2008 at 11:13 AM, abdul muhammed <abdulmuri@gmail.com>
wrote:
> hi,
>
> what does it mean to invert the 7th bit of the MAC address when
> calculating
> ipv6 address of an interface
>
> i.e
>
> my interface mac address= 0030.947e.e582 when inverted gives
> 0230.947e.ef82and when we introduce FFFE into the mac address it
> gives 0230:94FF:FE7E:EF82.
>
> how does inverting the 7th bit produce 0230.947e.e582
>
> thank u
>
> --
> Abdul Muhammed Murtala
> AMerican University of Nigeria
> Lamido Zubairu way, Yola
> Adamawa
> +2348052001153, +2348056201237
>
> Network Manager
> MCSE,MCDBA,MCSA,OCPDBA,CCNA,CCIE Written.
>
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-- Gregory Wendel Springfield VA, 22153
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