From: Rich Collins (nilsi2002@gmail.com)
Date: Sun Feb 24 2008 - 01:17:40 ARST
This ACL looks familiar.
permit 192.168.5.0 0.0.8.0
permit 192.168.10.0 0.0.4.0
Third octet in binary - X is the wildcard 8 and 4 respectively.
5 and 13 X101
10 and 14 1X10
-Rich
On 2/22/08, Snyder, Daniel P <DPSnyder@hammond.k12.in.us> wrote:
>
> Say I have the following networks...
>
>
>
> 192.168.0.0/24 - 192.168.15.0/24
>
>
>
> I need to make a filter on routes coming in. The router can only accept
> the
> following routes:
>
>
>
> 192.168.5.0
>
> 192.168.10.0
>
> 192.168.13.0
>
> 192.168.14.0
>
>
>
> The thing is it can only be a 2 line acl... Is this even possible??
This archive was generated by hypermail 2.1.4 : Sat Mar 01 2008 - 16:54:49 ARST