From: Darby Weaver (darbyweaver@yahoo.com)
Date: Sat Dec 15 2007 - 15:11:45 ART
I think I'd first ask what are the requirements?
1 Line, 2 Lines, or maybe 4 Lines and it looks like
you want to permit them, right?
Off the top and I think I can guarantee you a 13 will
not match a 14 nor will it match a 3.
0000 1101 = 13
0000 1110 = 14
0000 0011 = 3
See the problem?
To match both of these you would need x.x.0.0
0.0.15.255
No for the previous octet you are looking for 208 and
192. Looks simple enough.
1100 0000
1101 0000
For this it looks like: x.192.0.0 0.16.0.0
So...
permit ip 150.50.40.0 0.0.0.255 168.192.0.0
0.16.15.255
So... correct me if it is too early for me - I did
just wake up from studying a bit late last night.
--- "Athaide, Dwayne" <DAthaide@eprod.com> wrote:
> Would the following match
>
> 168.192.3.0/24
>
> 168.192.14.0/24
>
> 168.208.11.0/24
>
> 168.208.14.0/24
>
> 168.208.3.0/24
>
> 168.192.11.0/24
>
>
>
> permit ip 150.50.40.0 0.0.0.255 168.192.3.0
> 0.16.13.255
>
>
>
>
>
>
>
> Thanks
>
>
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