From: Athaide, Dwayne (DAthaide@eprod.com)
Date: Tue Dec 11 2007 - 13:50:20 ART
How would you match the curl brackets in an AS-SET for example 610,
{1,2}, 600 $
Thanks
-----Original Message-----
From: nobody@groupstudy.com [mailto:nobody@groupstudy.com] On Behalf Of
Scott Morris
Sent: Tuesday, December 11, 2007 8:43 AM
To: 'Chan Hong'; 'certification Cisco'
Subject: RE: Regular Expression
Solve it like you would a math equation... by that, things inside ()
are
solved separately.
So:
* = 0 or more of preceeding character.
[] = range representing a single character. So the * immediately
follows
the [0-9], which means 0 or more number values.
_ = parsing character, which in an AS Path means beginning of line,
space,
or end of line.
So you end up with:
1 followed by 2 followed by 3 followed by 4 followed by (space or end of
line). If space then you have 0 or more integer characters and then
MUST
have end of line. So no more spaces (extra AS numbers) can be included.
In your show command, you didn't force the end of the string, so all of
those match. it's kind of like using "show ip bgp regexp 100" and you
will
find positive results from 100, 1100, 1001, 10011, 10087, 21004, etc.
because they all include the string "100" with no other restrictions!
HTH,
Scott Morris, CCIE4 (R&S/ISP-Dial/Security/Service Provider) #4713,
JNCIE-M
#153, JNCIS-ER, CISSP, et al.
CCSI/JNCI-M/JNCI-ER
VP - Technical Training - IPexpert, Inc.
IPexpert Sr. Technical Instructor
A Cisco Learning Partner - We Accept Learning Credits!
Telephone: +1.810.326.1444
Fax: +1.810.454.0130
http://www.ipexpert.com
-----Original Message-----
From: nobody@groupstudy.com [mailto:nobody@groupstudy.com] On Behalf Of
Chan
Hong
Sent: Tuesday, December 11, 2007 8:53 AM
To: certification Cisco
Subject: Regular Expression
Dear all,
I want to ask about regulat expression, * and [], () From my
understanding,
show ip bgp regxp 1234(_[0-9]*)$ will show all bgp route with as path
starting from 1234 and zero or one other as in the as path (eg., 1234
4321,
or 1234) But if without $, the result is all bgp routes with as path
starting from 1234 and 0 or MORE other as in the as path (eg., 1234,
1234
4321, 1234 4321 4567 122) why??
$ means the end of the pattern, but which symbol mean the repeat
pattern???
The * is inside (), next to [0-9]. The
repeat pattern should apply on character 0-9 only. Inside the (), there
is a
_ also, which can be "space" or end of string. Why without the $, the
show
ip bgp rexp 1234(_[0-9]*) can be something like:
R1#sh ip bgp regexp
1234(_[0-9]*)
BGP table version is 3, local router ID is 10.155.129.1 Status
codes: s suppressed, d damped, h history, * valid, > best, i - internal,
r
RIB-failure, S Stale Origin codes: i - IGP, e - EGP, ? - incomplete
Network Next Hop Metric LocPrf Weight Path
*> 3.0.0.0
10.155.129.2 200 0 1234 103 80 i
*> 8.5.250.0/24
10.155.129.4 200 0 1234 10 13 15 i
*> 15.149.2.0/24
10.155.129.4 200 0 1234 10 i
Regards,
Howard
Yahoo! g62d8
e. e(f;g%o<
fd= e&d=i2g/i;e."! h+
e
e>
http://hk.promo.yahoo.com/security/index.htmld:h'#f4e$!
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