From: Toh Soon, Lim (tohsoon28@gmail.com)
Date: Tue Oct 30 2007 - 12:20:38 ART
Hi,
Kindly correct me if I'm wrong.
A Mapping Agent selects the RP for a given multicast group address range(s)
based on the candidate RPs' IP address. The highest candidate RP IP address
is selected.
In other words, the tie-breaker is purely based on C-RP's IP address.
Thank you.
B.Rgds,
Lim TS
On 10/30/07, hadek.el-ayachi@nsn.com <hadek.el-ayachi@nsn.com> wrote:
>
> The task is to make R5 RP for all but 239/8, so you should use selective
> acl denying 239/8.
> Otherwise, the RP is selected based on longest match (before prefering
> low priority, high hash or high IP address)
> All that I know!
> -----Original Message-----
> From: nobody@groupstudy.com [mailto:nobody@groupstudy.com] On Behalf Of
> ext Toh Soon, Lim
> Sent: mardi 30 octobre 2007 13:51
> To: ccielab@groupstudy.com
> Subject: Auto-RP : Multiple C-RPs for the same group
>
> Hi Group,
>
> I have the following Auto-RP scenario:
>
> R7
> --
> 1. C-RP for 239.0.0.0/8
> 2. RP address 200.0.0.7
>
> R5
> --
> 1. Mapping agent
> 2. C-RP for all groups except 239.0.0.0/8 3. RP address 200.0.0.5
>
> I guess one way of configuring this is, we define an ACL on R5 that
> matches groups 224 until 238 (summarizing whatever we can) and let R5
> announce this group-list.
>
> Another way I'm thinking of is, since R7's IP address is higher than
> R5's, I will configure R5 to announce, by default, all groups. When R5
> and R7 contend for group 239.0.0.0/8, R7 will win. R5 will be RP for the
> rest of the groups. In the end, this solution meets the task requirement
> and does not violate any rules but is it acceptable?
>
> Please share if you have other methods.
>
>
> Thank you.
>
> B.Rgds,
> Lim TS
>
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