From: Herbert Maosa (asawilunda@googlemail.com)
Date: Thu Oct 18 2007 - 17:32:00 ART
Eric,
I assume you are maintaining bytes as the unit for Bc and ms as the unit for
TC ? In that case Bc of 64 Bytes and Tc of 10ms is giving me CIR = 512Kbps,
using the formula CIR = Bc/Tc.
In any case, what will happen to a packet that is larger than the maximum
rate permitted will depend on whether you are shaping or policing. If you
are shaping, then the packet will simply be queued in the shaping queue from
which it will then be sent at CIR. If you are policing then it will depend
on the configured action for non-conforming traffic.
Herbert.
On 10/18/07, Eric Phillips <ephillips@squick.cc> wrote:
>
> Hi all,
>
> I have searched through the GroupStudy archives, read through Odem's DQOS
> book, and checked out the DOC CD, but have not found a clear answer to a
> question that has been on my mind.
>
> If I enable shaping with a very small Bc, for example, a Tc of 10, and a
> Bc
> of 64, that should shape to 64kbit/sec, right? Now if I do not enable
> link
> fragmentation, and a large packet, perhaps 1400 bytes comes through, what
> will happen? It can not be sent in a single Tc, and it can not be
> fragmented because link fragmentation is disabled. Also assume that I
> have
> no Be, or a Be too small to allow 1400 bytes to accumulate between Bc and
> Be.
>
> This seems like an awfully simple question, but I have not found a clear
> answer anywhere.
>
> Thank you very much,
>
> Eric
>
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-- Kindest regards, hm
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