From: Joseph Brunner (joe@affirmedsystems.com)
Date: Mon Sep 24 2007 - 22:14:59 ART
Let's look at the numbers first as given to us by the task
AR = 7,500,000 bits per second
CIR = 5,000,000 bits per second
Tc = 32 ms
Be = AR-CIR = 2,500,000
So if we divide 1000ms / tc (32ms) we are given 31.25, now we just need to
divide our cir by 31.25 to find our "bits per interval, sustained"
So guess what?
5,000,000 / 31.25 = 160,000 (WHAT WE CAN SEND SUSTAINED PER TC)
So now let's find our "bits per interval, excess" (BE)
AR-CIR = 2,500,000 / 31.25 = 80000
So the command under class class-default is
shape average 5000000 160000 80000
And we verify with... (look at the "interval")
rack1r2#sh policy-map int s0/0
Serial0/0
Service-policy output: FRPOLICY
Class-map: class-default (match-any)
2 packets, 148 bytes
5 minute offered rate 0 bps, drop rate 0 bps
Match: any
Traffic Shaping
Target/Average Byte Sustain Excess Interval Increment
Rate Limit bits/int bits/int (ms) (bytes)
5000000/5000000 30000 160000 80000 32 20000
Adapt Queue Packets Bytes Packets Bytes Shaping
Active Depth Delayed Delayed Active
- 0 2 148 0 0 no
-----Original Message-----
From: nobody@groupstudy.com [mailto:nobody@groupstudy.com] On Behalf Of
slevin kremera
Sent: Monday, September 24, 2007 8:16 PM
To: Cisco certification
Subject: iewb v4.1 lab 9 task 7.1 FRTS
can some one explain how did he get the burst value of 160000
This archive was generated by hypermail 2.1.4 : Sat Oct 06 2007 - 12:01:15 ART