From: Ben (bmunyao@gmail.com)
Date: Sun Sep 16 2007 - 09:27:48 ART
CCIE1101,
I personally found the following URL very helpful for learning this:
http://www.internetworkexpert.com/resources/01700370.htm
HTH
Ben
On 9/16/07, Brian Dennis <bdennis@internetworkexpert.com> wrote:
>
> First start by converting them to binary and then line them up as below.
> For the address portion of the ACL bring down any bits that match for the
> whole column. If the bits in a column don't match you can put anything in
> there (0 or 1) since you are going to "ignore" that column anyways with
> the wildcard mask. Now for the wildcard mask if all the bits in a column
> match put a 0. If all the bits in column do not match put a 1. Convert
> these back to decimal and you're all set ;-)
>
> 3rd Octet:
>
> 00000001 = 1
> 00000001 = 1
> 00000001 = 1
> 00000001 = 1
> 00000011 = 3
> 00000011 = 3
> 00000011 = 3
> 00000011 = 3
> ------------
> 00000001 = 1 Address
> 00000010 = 2 Wild Card Mask
>
> 4th Octet:
>
> 00000010 = 2
> 00010010 = 18
> 00001010 = 10
> 00011010 = 26
> 00000010 = 2
> 00010010 = 18
> 00001010 = 10
> 00011010 = 26
> -------------
> 00000010 = 2 Address
> 00011000 = 24 Wild Card Mask
>
> Personally I would have just put "access-list 1 permit any" ;-)
>
> Brian Dennis, CCIE4 #2210 (R&S/ISP-Dial/Security/SP)
> bdennis@internetworkexpert.com
>
> Internetwork Expert, Inc.
> http://www.InternetworkExpert.com
> Toll Free: 877-224-8987
> Direct: 775-745-6404 (Outside the US and Canada)
>
>
> >----- Original Message -----
> Subject: Re: Traffic Filtering ...
> Date: Sat, September 15, 2007 22:25
> From: "ccie1101" <ccie1101@gmail.com>
>
> > Hi,
> > Can someone explain how do I summarize this to 1 ACL ...
> > The IPs that needs to be summarize is as follows :-
> >
> > 200.0.1.2
> > 200.0.1.18
> > 200.0.1.10
> > 200.0.1.26
> > 200.0.3.2
> > 200.0.3.10
> > 200.0.3.18
> > 200.0.3.26
> >
> > The solution given was 200.0.1.2 0.0.2.24 but I do not understand how
> to
> > get this.
> >
> > Can someone help explain this ?
> >
> > Thank you,
> >
> > ccie1101.
> >
> > _______________________________________________________________________
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