From: Djerk Geurts (djerk@djerk.nl)
Date: Mon Jul 09 2007 - 15:09:20 ART
Correct, the two tasks I mailed earlier today are possible in 'very' short
notation.
Impress means use shortest config: Task#1 can be done in 4 lines, task#2 in
2 lines
Djerk
> -----Original Message-----
> From: nobody@groupstudy.com [mailto:nobody@groupstudy.com] On
> Behalf Of George Roman
> Sent: maandag 9 juli 2007 19:51
> To: Djerk Geurts; ccielab@groupstudy.com
> Subject: Re: Funky acl question-Check if this is correct
>
> Hmm, then in my opinion that is not possible because the last
> 4 subnets (10,
> 12, 13, 15) have nothing in common except for that "1" on the
> 4-th position
> (8 in decimal). i cannot group them in just two statements
> without something
> that they have in common.
> Am i right?
>
> George
>
> On 7/9/07, Djerk Geurts <djerk@djerk.nl> wrote:
> >
> > George,
> >
> > > #this one permits only network .5.0
> > > access-list 1 permit 10.0.5.0 0.0.0.255
> > > #this one permits all networks from 8 to 15
> > > access-list 1 permit 10.0.8.0 0.0.7.255
> >
> > Your stament is correct, however as I read the question
> only the showed
> > networks should be allowed all others in the range should be denied.
> >
> > > Take these subnets:
> > >
> > > 10.0.5.0/24
> > > 10.0.10.0/24
> > > 10.0.12.0/24
> > > 10.0.13.0/24
> > > 10.0.15.0/24
> > >
> > > And write two-line ACL to permit them without permitting
> 10.0.6.0/24,
> > > 10.0.7.0/24..and the other subnets included in the range.
> >
> > Eric, am I correct in my assumption?
> >
> > Djerk
> >
> >
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