If AD = FD in EIGRP

From: Naresh Myaka (want2bccie@gmail.com)
Date: Wed Jun 13 2007 - 04:33:14 ART

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Hi GS,

We all are aware that in EIGRP, FC is met if AD is less then FD. I'm not
sure whether if neighbor's AD = FD will it still meet the FC and also will
it be in the topology table.

Regards,
Naresh M.

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