Re: redistribute connected with a route map

From: Erol Asim (erol.asim@gmail.com)
Date: Mon May 07 2007 - 17:05:25 ART


Sorry, I should have made myself more clear - loopback 1 is required
to be advertised by redistributing ospf into rip. Loopback 1 cannot be
added to OSPF. Is this possible? Thank you for the response.

On 5/7/07, Brian McGahan <bmcgahan@internetworkexpert.com> wrote:
> You didn't enable OSPF on the Loopback1 interface. Look at the
> "show ip ospf interface brief" output and you'll see what interfaces are
> candidate to be redistributed. If you want that advertised into RIP
> either add the network 192.168.2.0 command under RIP, the redistribute
> connected command under RIP, or enable OSPF on the interface.
>
>
> HTH,
>
> Brian McGahan, CCIE #8593 (R&S/SP)
> bmcgahan@internetworkexpert.com
>
> Internetwork Expert, Inc.
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>
> -----Original Message-----
> From: nobody@groupstudy.com [mailto:nobody@groupstudy.com] On Behalf Of
> Erol Asim
> Sent: Monday, May 07, 2007 2:38 PM
> To: ccielab@groupstudy.com
> Subject: redistribute connected with a route map
>
> Hi Guys,
>
> I'm perplexed by problem I don't understand. For some reason when I
> redistribute ospf into rip, loopback 1 on r3 is not seen on r1. From
> my understanding, redistribute ospf will take all routes in the ospf
> database and advertise them to r1. Is this correct? If so, why isn't
> this occurring? Does this have something to do with route map and
> redistribtion on r3? Debug on r1 confirms r3 is not advertising the
> route. Can anyone help? Topology is below:
>
> ================r5
> hostname r5
> !
> interface Ethernet0
> ip address 10.0.0.1 255.0.0.0
> no shut
> !
> router rip
> network 10.0.0.1
> ================r3
> hostname r3
> !
> interface Loopback0
> ip address 192.168.1.3 255.255.255.0
> !
> interface Loopback1
> ip address 192.168.2.3 255.255.255.0
> !
> interface Loopback2
> ip address 192.168.3.3 255.255.255.0
> !
> interface Ethernet0/0
> ip address 10.0.0.3 255.0.0.0
> ip ospf net point-to-point
> !
> router ospf 1
> redistribute connected subnets route-map LOOP_1
> network 10.0.0.3 0.0.0.0 area 0
> network 192.168.3.3 0.0.0.0 area 0
> no auto
> !
> router rip
> redistribute ospf 1 metric 3
> net 10.0.0.3
> network 192.168.1.3
> no auto-summary
> !
> route-map LOOP_1 permit 10
> match interface loopback 1
> ================r1
> hostname r1
> !
> interface Ethernet0
> ip address 10.0.0.1 255.0.0.0
> no shut
> !
> router rip
> network 10.0.0.1
> ======================================
> C 10.0.0.0/8 is directly connected, Ethernet0
> R 192.168.1.0/24 [120/1] via 10.0.0.3, 00:00:00, Ethernet0
> R 192.168.3.0/24 [120/3] via 10.0.0.3, 00:00:00, Ethernet0
> r1#
> ======================================
> C 10.0.0.0/8 is directly connected, Ethernet0/0
> C 192.168.1.0/24 is directly connected, Loopback0
> C 192.168.2.0/24 is directly connected, Loopback1
> C 192.168.3.0/24 is directly connected, Loopback2
> r3#
> ======================================
> C 10.0.0.0/8 is directly connected, Ethernet0
> O E2 192.168.2.0/24 [110/20] via 10.0.0.3, 01:59:34, Ethernet0
> 192.168.3.0/32 is subnetted, 1 subnets
> O 192.168.3.3 [110/11] via 10.0.0.3, 01:59:34, Ethernet0
> r5#
>
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