From: Sam (syed_wsu@yahoo.com)
Date: Wed Apr 25 2007 - 23:20:38 ART
Hi All,
I know similar questions has been posted in the
archives as i am nto sure of my solution can soemone
please verify if this is correct and if not then what
will be the right answer.
Given IPv6 Prefix:- 2001:abc:123::/48
Interface Ip address 7.7.30.3
I have to configure IPv6 address on the interface
whose host portion must be made of EUI-64 format,
mask on the interface must be/64
remaining bits of the network address should be made
of 3rd octet of the IPv4 address.
Proposed Solution:
3rd octet of IPv4 is 30
30 in Hex is IE
so the Ipv6 address would be
2003:abc:123:1e::/64 eui-64
it appears to simple to be true...please advise.
Thnaks
Sam
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