From: M S (michaelgstout@hotmail.com)
Date: Thu Mar 22 2007 - 11:32:31 ART
No, sorry for not being clear. Three addresses
45.194.169.10561.202.173.24341.234.41.250I want the most specifcic one line
access-list to permit these
Date: Wed, 21 Mar 2007 21:36:15 -0700From: jmullan78@gmail.comTo:
michaelgstout@hotmail.comSubject: Re: subnetmask problemCC:
ccielab@groupstudy.comsorry, a bit confused. You have 2 examples here
194,202,234 and 2nd one 40,169,173,41 ?
On 3/21/07, M S <michaelgstout@hotmail.com> wrote:
Hello:I am looking at a summerization problem that requires the use of the
mostefficient one line access-list to permit three ip addresses to telnet into
a routerCan anybody verify my logic for these three numbers, please?194 = 1100
0010202 = 1100 1010234 = 1110 1010------------------------40 = 0010 1000So
the mask for this Octet should be 40, is that corrrect? 169 = 1010 1001173 =
1010 110141 = 0010 1001------------------------132 = 1000 0100So the mask
for this octet should be 132, is that correct.Isthere a calculator shortcut
that can be used to gain these mask values? Thank you very
kindly.----------------------------------------------------------------------
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