From: Edison Ortiz (edisonmortiz@gmail.com)
Date: Tue Jan 16 2007 - 11:24:14 ART
> If the packet is larger than Bc, will this packet be fragmented to fit
> into Bc?
Yes.
> If not, how the Tc can affect the voice latency?
You need to avoid fragmentation on voice traffic. That's the reason you need
to lower Tc - send packets faster.
----- Original Message -----
From: "dampened" <cheechew@hotmail.com>
To: ""Edison Ortiz"" <edisonmortiz@gmail.com>
Cc: "Cisco certification" <ccielab@groupstudy.com>; <nobody@groupstudy.com>;
""prashant shukla"" <shukla_cisco@yahoo.co.in>
Sent: Tuesday, January 16, 2007 5:40 AM
Subject: Re: IEWB--- Be calculations.
>
> Some confusion here. I am not sure what is the relation between
> fragmentation and Bc value.
>
> If the packet is larger than Bc, will this packet be fragmented to fit
> into Bc?
> If not, how the Tc can affect the voice latency?
>
> Please comment.
>
>
>
>
>
>
>
> "Edison Ortiz" <edisonmortiz@gmail.com>
> Sent by: nobody@groupstudy.com
> 01/15/2007 12:14 AM
> Please respond to
> "Edison Ortiz" <edisonmortiz@gmail.com>
>
> To
> "prashant shukla" <shukla_cisco@yahoo.co.in>, <ccielab@groupstudy.com>
> cc
>
> Subject
> Re: IEWB--- Be calculations.
>
>
>
>
>
> #1
> 128k or 384k now becomes your AR and the Tc is given for the circuit on
> that
> case.
>
> Be = (128-64)x32/1000
> Be = (384-64)x64/1000
>
> Forget about the 512k AR, it's there to confuse you.
>
> #2
>
> Other signs to look for, if you have voice on the circuit. Voice latency
> needs the minimum
> Tc value which is 10ms. Then you need to fragmented, example:
>
> Bc = (CIR*Tc)/1000
> Bc = (512000*10)/1000 which is Bc 5120 (640 bytes) - passes fragmentation
> rule
>
> Whereas if you have
>
> Bc = (512000*32)/1000 which is Bc 16384 (2048 bytes) - fails fragmentation
> rule and this
> packet must be fragmented.
>
>
>
>
>
> ----- Original Message -----
> From: "prashant shukla" <shukla_cisco@yahoo.co.in>
> To: <ccielab@groupstudy.com>
> Sent: Sunday, January 14, 2007 2:31 AM
> Subject: IEWB--- Be calculations.
>
>
>> Gurus,
>>
>> This is what i understand and need clarification on.
>> AR= 512Kbps ; CIR = 64Kbps.
>>
>> Bc= CIR x Tc / 1000
>> Be= (AR-CIR) x Tc / 1000
>>
>> #1. So im able to the above calculation if the question mentions "
>> allow
>> DLCi 103 to burst upto port speed " then the Be formula works with
>> (512-64)kbps x TC/1000, my doubt comes when the question says, " Allow
>> the
>> DLCI to burst upto 128 /384 Kbps for 32ms or 64ms etc etc." here how to
>> look for the Be, as the burst is not upto port speed, so im struggling to
>> find a "Universal rule".
>>
>> #2.Secondly; in questions where its not mentioned any Tc value I would
>> like to
>> go for 125ms as default, what other "Signs" i should look for where the
>> Tc value can be influenced, e.g. In one IEWB it mentions " The packet
>> above 960 bytes should be fragmented". Is this a catch!! as the the Tc
>> chosen made .
>>
>> hope i was clear enough... :-)
>>
>> Shukla.
>>
>>
>>
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