From: Hugo Viana (viana2005@gmail.com)
Date: Sun Dec 10 2006 - 11:58:01 ART
Mohamed, using only the ODD networks:
Take the logical AND of these addresses, to find address:
0 1 0 1 0 0 0 1
0 1 0 1 0 0 1 1
0 1 0 1 0 1 0 1
0 1 0 1 0 1 1 1
---------------------
0 1 0 1 0 0 0 1 -> 81 in decimal notation
And and logical XOR, to find de *the wildcard*:
0 1 0 1 0 0 0 1
0 1 0 1 0 0 1 1
0 1 0 1 0 1 0 1
0 1 0 1 0 1 1 1
---------------------
0 0 0 0 0 1 1 0 -> 6 in decimal notation
Final result: 208.10.81.0 0.0.6.255, match only the ODD networks.
On 12/10/06, Tandou Mohamed <dtandou@yahoo.com> wrote:
>
> Hi keiko,
> yes they are talking about the the 3rd octet. see i put them in binary
> how do i go from here?
>
> 0 1 0 1 0 0 0 0
> 0 1 0 1 0 0 0 1
> 0 1 0 1 0 0 1 0
> 0 1 0 1 0 0 1 1
> 0 1 0 1 0 1 0 0
> 0 1 0 1 0 1 0 1
> 0 1 0 1 0 1 1 0
> 0 1 0 1 0 1 1 1
>
> thanks, for your input.
>
> Mohamed
>
>
> Heiko Liedtke <heiko.liedtke@gmx.net> wrote:
> Hi,
>
> ODD in which octett? I guess there are talking about the 3rd octett...
> If you write down some odd and some even networks in binary notation,
> you can see, that there is always the least significant bit (the 2EXP0)
> which
> makes the differens between ODD and EVEN.
> Knowing this you can easily write an ACL to filter on this bit.
>
>
> Heiko
>
>
> Tandou Mohamed schrieb:
>
> >Hello GS
> > can someone explain to me the best way to filter access-list.
> > The question asked to permit only ODD route without using distribute
> list
> > When i do show ip route this is what i get
> >
> > 208.10.80.0/24
> > 208.10.81.0/24
> > 208.10.82.0/24
> > 208.10.83.0/24
> > 208.10.84.0/24
> > 208.10.85.0/24
> > 208.10.86.0/24
> > 208.10.87.0/24
> > How do i filter odd route from here?
> >
> > Thanks
> >
> > Mohamed
> >
> >
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