From: Sergio Silva (spmsilva@gmail.com)
Date: Mon Nov 06 2006 - 09:12:58 ART
That looks like a odd and even load balance, the example is based on
splitting the load 0123 and 4567 didnt specifiy odd even,
How would you work that out?
Thanks
S
On 11/6/06, Ivan <ivan@iip.net> wrote:
>
> IMO it is not nessesary such distribution of RP. May be
> 1, 3, 5, 7
> 0, 2, 4, 6
>
> This depend of hash algorithm.
> May be lab it up help understanding.
>
> On Monday 06 November 2006 00:07, Cisco Key wrote:
> > Correct me if I am wrong but its seen the same as a Subnet Mask
> > So for example
> >
> > 225.1.1.0
> > 225.1.1.1
> > 225.1.1.2
> > 225.1.1.3
> > 225.1.1.4
> > 225.1.1.5
> > 225.1.1.6
> > 225.1.1.7
> >
> > Statement would be - #ip pim bsr-candidate loopback 29 as in /29
> >
> > If you want to load balance then
> > 225.1.1.0
> > 225.1.1.1
> > 225.1.1.2
> > 225.1.1.3
> >
> > Statement would be - #ip pim bsr-candidate loopback 30 as in /30
> >
> > 225.1.1.4
> > 225.1.1.5
> > 225.1.1.6
> > 225.1.1.7
> >
> > Statement would be - #ip pim bsr-candidate loopback 30 as in /30
> >
> > Please tell me if this is correct
> >
> > Regards
> > Paul
> >
> > On 03/11/06, Adhu Ajit <adhu_ajit@yahoo.com> wrote:
> > > Folks,
> > >
> > > ip pim bsr-candidate [intf] [hash-mask-length] [priority}
> > >
> > > I looked this up in the Cisco CD and I got:
> > >
> > > hash-mask-length: Length of a mask (32 bits maximum) that is to be
> ANDed
> > > with the group address before the hash function is called. All groups
> > > with the same seed hash (correspond) to the same RP. For example, if
> this
> > > value is 24, only the first 24 bits of the group addresses matter.
> This
> > > fact allows you to get one RP for multiple groups.
> > >
> > >
> > > I dont fully understand this option. Can someone please explain with
> an
> > > example ?
> > >
> > > Thanks,
> > > Adhu.
> > >
> > >
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> --
> Ivan
>
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