From: emmanuel daniel (emmanueldan@gmail.com)
Date: Mon Oct 23 2006 - 01:18:13 ART
Hi guys What scott says is right but i have no said the same question but
only similar question.
Regards
Emmanuel
On 10/23/06, WorkerBee <ciscobee@gmail.com> wrote:
>
> You can force R2 to initial the BGP peering by applying ACL to the PIX
> interfaces:
>
> ACL inside
> deny tcp host R1_Lo host R2_Lo eq 179
>
> ACL outside
> permit tcp host R2_Lo host R1_Lo eq 179
>
> Hence, the ACL will force the peering R1 (179) <--------> R2 (High Port).
>
>
>
> On 10/23/06, emmanuel daniel <emmanueldan@gmail.com> wrote:
> > Hi
> >
> > I took my sec exam last week and i couldnt pass mainly i got less points
> in
> > bgp. i Wantt to know where i screwed up can any one help me out here is
> my
> > problem the qustion was some what similar to this
> >
> >
> > R1 e0/0 183.1.123.1 -------- (inside 183.1.123.10) pix (outside
> 183.1.124.10
> > )---------183.1.124.2 e0/0 r2
> > lo 150.100.1.1
> > lo
> > 150.100.2.2
> > (BGP AS
> > 54)
> > (BGP AS 55)
> >
> > the question is r1 which is bgp as 54 wants make an ebgp peering with r2
> > with is in as 55. using thee loopbacks and make the peering such that
> r1
> > always uses a foreign port of 179. i thought its given just to confuse
> me
> > and i didnt solve it bec default bgp port is 179.
> >
> >
> > Regards
> > Emmanuel.
> >
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