From: Hafizur Rahman \(UK\) (hafizur.rahman@uk.didata.com)
Date: Thu Aug 17 2006 - 19:51:33 ART
Hi Imarn,
Could you please explain why subnet mask is 10 bit?
Thanks in advance
hafi
-----Original Message-----
From: nobody@groupstudy.com [mailto:nobody@groupstudy.com] On Behalf Of
Moin, Imran
Sent: 17 August 2006 03:15
To: Scott Morris; KC; Group Study (E-mail); leigh@net-elite.org
Subject: RE: IPv6
Scott,
Can you please confirm that if my IPv4 address is 176.1.245.55/24, then
the IPv6 Site-local address would be FEC0:0:0:F5::37/10. I just want to
make sure that I am doing this conversion correctly.
Thanks,
Imran Moin.
-----Original Message-----
From: nobody@groupstudy.com [mailto:nobody@groupstudy.com] On Behalf Of
Scott Morris
Sent: Saturday, April 08, 2006 6:29 PM
To: 'KC'; 'Group Study (E-mail)'; leigh@net-elite.org
Subject: RE: IPv6
FEC0:0:0:2::2/64
A site-local address is:
FEC0:0:0:(16-bit-subnet):x:x:x:x/64 where the x's are 64 bits of host
ID.
HTH,
Scott Morris, CCIE4 (R&S/ISP-Dial/Security/Service Provider) #4713,
JNCIE #153, CISSP, et al.
CCSI/JNCI
IPExpert CCIE Program Manager
IPExpert Sr. Technical Instructor
swm@emanon.com/smorris@ipexpert.com
http://www.ipexpert.com
PS. While it doesn't matter in this example, don't forget your IPv6
addresses are in hex! So if your third octet were 11, that would be B
where the 2 is for the above subnet ID!
-----Original Message-----
From: nobody@groupstudy.com [mailto:nobody@groupstudy.com] On Behalf Of
KC
Sent: Saturday, April 08, 2006 6:22 PM
To: Group Study (E-mail); leigh@net-elite.org
Subject: Re: IPv6
I want to confirm this because either the answer in workgroup is wrong
or me , if i correctly understand it.
On 4/8/06, KC <kanwal.chawla@gmail.com> wrote:
>
> Hey Guys
>
> I took the lab 2 days back , and i failed . I just wanna know about
> one question which is a doubtful to me .
>
> Say if the question is :- Configure IPv6 Site local address on
> loopback
> 11.11.2.2 . Use subnet id as 3rd octet of your IPv4 address and
> interface id as 4th octet of ipv4. What will be the IPv6 address and
> How
??
>
> Any inputs would be appreciated.
>
> Thanks in advance
This archive was generated by hypermail 2.1.4 : Fri Sep 01 2006 - 15:41:57 ART