From: Paul Dardinski (pauld@marshallcomm.com)
Date: Mon Jul 03 2006 - 12:08:35 ART
Dave,
From below, tc would be cir=bc/tc, so 8000=12000/tc or tc=12000/8000=1.5
seconds.
Be is totally separate from the equation. The below statement would
allow an excess burst of 16000bps over the same 1.5 second tc span.
I never received any real answer as to the difference of police cir vs
just police, so I'm assuming they are the same.........
-----Original Message-----
From: David Timmons [mailto:masterdt@yahoo.com]
Sent: Monday, July 03, 2006 10:58 AM
To: Paul Dardinski; Cisco certification
Subject: Re: Police "cir" vs police
HI,
I have had the same questions. I am also having
problems understanding how the Bc is actually
interpreted. For example, what does this really mean?
police cir 8000 bc 1500 be 2000
Do we use the CIR to compute a time interval? Is it
just 1500 per second? Do we have a way to compute a
time interval? I have only found a recommended value
for Bc and Be from Cisco:
normal burst = configured rate * (1 byte)/(8 bits) *
1.5 seconds
extended burst = 2 * normal burst
Many QOS books say that policing does not really use
Tc the same as in shaping. I just don't understand how
we evaluate the time period for the Bc and Be.
--- Paul Dardinski <pauld@marshallcomm.com> wrote:
> I see the "police cir" command in the cco only
> occasionally. I can't
> seem to locate difference between using just police
> command vs police
> cir (mqc).
>
>
>
> Any help?
>
>
>
> PD
>
>
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