From: Scott Morris (swm@emanon.com)
Date: Sat Jul 01 2006 - 15:03:53 ART
Play around with the binary. :)
But keep in mind that not every question like this needs to be answered with
only ONE line. No more, no less. But break these things into binary and
see what answers leap out at you.
HTH,
Scott Morris, CCIE4 (R&S/ISP-Dial/Security/Service Provider) #4713, JNCIE
#153, CISSP, et al.
CCSI/JNCI
IPExpert CCIE Program Manager
IPExpert Sr. Technical Instructor
smorris@ipexpert.com
http://www.ipexpert.com
-----Original Message-----
From: nobody@groupstudy.com [mailto:nobody@groupstudy.com] On Behalf Of
Faryar Zabihi (fzabihi)
Sent: Saturday, July 01, 2006 7:28 AM
To: ELDHO PAUL; Sami
Cc: ccielab@groupstudy.com
Subject: RE: Access list
What if I have,
192.172.1.0
192.172.2.0
192.172.3.0
192.172.4.0
192.172.5.0
192.172.6.0
192.172.7.0
192.172.8.0
192.172.9.0
192.172.10.0
192.172.11.0
192.172.12.0
192.172.13.0
192.172.14.0
192.172.15.0
150.16.1.0
I need to keep
192.172.8.0
192.172.9.0
192.172.10.0
192.172.11.0
150.16.1.0
Routing protocol RIP. Catch being ONLY ONE line ACL First I tried to grab
the networks I need but the 150.16.1.0 I could not include with one line in
an acl. Then I tried to get the ones I need to filter out and offset by 15.
my question is how do I match 192.172.1.0 192.172.2.0 192.172.3.0
192.172.4.0 192.172.5.0 192.172.6.0 192.172.7.0 192.172.12.0 192.172.13.0
192.172.14.0 192.172.15.0
Thanks in advance,
Faryar
-----Original Message-----
From: nobody@groupstudy.com [mailto:nobody@groupstudy.com] On Behalf Of
ELDHO PAUL
Sent: Saturday, July 01, 2006 6:20 AM
To: Sami
Cc: ccielab@groupstudy.com
Subject: Re: Access list
A more currect answer seems to be
51.1.0.1 0.0.0.8
We will get the first portion 51.1.0.1 by doing an and opration of all the
four ip addresses and the wildcard portion by doing the XOR operation of all
the four ip addresses.
On 7/1/06, ELDHO PAUL <cciein2006@gmail.com> wrote:
>
> I think we can match it with 2 access lists
> 51.3.0.1 0.6.0.0
> 51.3.0.9 0.6.0.0
>
>
> On 7/1/06, Sami <sy1977@gmail.com> wrote:
> >
> > Group,
> >
> > One of the task say use minimum amount of line necessary to comple
> > this task.
> >
> > 51.3.0.1
> > 51.5.0.1
> > 51.7.0.1
> > 51.3.0.9
> > 51.5.0.9
> > 51.7.0.9
> >
> > How can I combine in one access list ?
> >
> > Thanks
> >
> > ____________________________________________________________________
> > ___ Subscription information may be found at:
> > http://www.groupstudy.com/list/CCIELab.html
This archive was generated by hypermail 2.1.4 : Tue Aug 01 2006 - 07:13:46 ART