From: ELDHO PAUL (cciein2006@gmail.com)
Date: Sat Jul 01 2006 - 10:54:41 ART
Aron,
Again I have my same question.
XOR:
00=0
11=0
01=1
I completely agree with it.
My friend going by this logic
1 XOR 1 XOR 1 XOR 1 should be 0.
I saw the internetwork expert link. I'm unable to understand the following
calculations Internetwork Experts have done.
00001010.00000000.00000000.00000000
00001010.00000100.00000000.00000000
00001010.00100000.00000000.00000000
00001010.00100100.00000000.00000000
**************************************************
00000000.00100100.00000000.00000000
Here if you look at the calculation in the second octect . The XOR result
contradicts with our above logic.(1 XOR 1=0 not 1).
Please explain.
Thanks
-Eldho
On 7/1/06, Aaron Pilcher <apilcher@itgcs.com> wrote:
>
> I have always used:
>
> AND:
> 00=0
> 11=1
> 01=0
>
> XOR:
> 00=0
> 11=0
> 01=1
>
> For reference, I believe this is a very clear document go through the
> examples. This document illuminated (or at least I think it did) this
> process.
>
> Let me know.
>
> http://www.internetworkexpert.com/resources/01700370.htm
>
> -aaron
>
> -----Original Message-----
> From: nobody@groupstudy.com [mailto:nobody@groupstudy.com] On Behalf Of
> ELDHO PAUL
> Sent: Saturday, July 01, 2006 8:14 AM
> To: Aaron Pilcher
> Cc: Sami; Faryar Zabihi (fzabihi); ccielab@groupstudy.com
> Subject: Re: Access list
>
> Aaron,
> I've a clarification
>
> >>>How do you get this answer.If you take the 7th bit in the 2nd octect.
> There are four ones. So If we XOR four ones the answer should be zero.
> Similarly the 6th bit. There are four ones. So the answer again should be
> zero.
> So the final answer becomes 00000000.00000000.00000000.00001000.
> Please currect me if I'm wrong.
>
> On 7/1/06, Aaron Pilcher <apilcher@itgcs.com> wrote:
> >
> > Here is what I came up with, logic included...(these do not take address
> > overlapping into consideration)(2nd one, it may be too early for me it
> > looks
> > odd)
> >
> > Internetwork expert has a really good example of this on their site.
> >
> >
> > 1st question
> >
> > ***************************************************
> > xor 00000000.00000110.00000000.00001000
>
> ---------------------------------------------------
> 51.3.0.1 00110011.00000011.00000000.00000001
> 51.5.0.1 00110011.00000101.00000000.00000001
> 51.7.0.1 00110011.00000111.00000000.00000001
> 51.3.0.9 00110011.00000011.00000000.00001001
> 51.5.0.9 00110011.00000101.00000000.00001001
> 51.7.0.9 00110011.00000111.00000000.00001001
> ---------------------------------------------------
> and 00110011.00000001.00000000.00000001
>
> access-list 1 permit 51.1.0.1 0.6.0.8
> ***************************************************
>
> 2nd question
> ***************************************************
>
> xor 01010110.10101100.00001011.00000000
> ---------------------------------------------------
> 192.172.8 11000000.10101100.00001000.00000000
> 192.172.9 11000000.10101100.00001001.00000000
> 192.172.10 11000000.10101100.00001010.00000000
> 192.172.11 11000000.10101100.00001011.00000000
> 150.16.1.0 10010110.00010000.00000001.00000000
> ---------------------------------------------------
> and 10000000.00000000.00000000.00000000
>
> access-list 1 permit 128.0.0.0 86.172.11.0
> ***************************************************
>
>
> -----Original Message-----
> From: nobody@groupstudy.com [mailto:nobody@groupstudy.com] On Behalf Of
> Sami
> Sent: Saturday, July 01, 2006 7:04 AM
> To: Faryar Zabihi (fzabihi)
> Cc: ELDHO PAUL; ccielab@groupstudy.com
> Subject: Re: Access list
>
> All,
>
> I am totally confused..which one is correct..everyone has different
> answer..IE lab 20 section 9.1 solution guide says
>
> 51.3.0.1 0.0.0.8
> 51.5.0.1 0.2.0.8
>
> Thanks
>
>
> On 7/1/06, Faryar Zabihi (fzabihi) < fzabihi@cisco.com> wrote:
> >
> >
> > What if I have,
> > 192.172.1.0
> > 192.172.2.0
> > 192.172.3.0
> > 192.172.4.0
> > 192.172.5.0
> > 192.172.6.0
> > 192.172.7.0
> > 192.172.8.0
> > 192.172.9.0
> > 192.172.10.0
> > 192.172.11.0
> > 192.172.12.0
> > 192.172.13.0
> > 192.172.14.0
> > 192.172.15.0
> > 150.16.1.0
> >
> > I need to keep
> > 192.172.8.0
> > 192.172.9.0
> > 192.172.10.0
> > 192.172.11.0
> > 150.16.1.0
> >
> > Routing protocol RIP. Catch being ONLY ONE line ACL
> > First I tried to grab the networks I need but the 150.16.1.0 I could not
> > include with one line in an acl. Then I tried to get the ones I need to
> > filter out and offset by 15. my question is how do I match
> > 192.172.1.0
> > 192.172.2.0
> > 192.172.3.0
> > 192.172.4.0
> > 192.172.5.0
> > 192.172.6.0
> > 192.172.7.0
> > 192.172.12.0
> > 192.172.13.0
> > 192.172.14.0
> > 192.172.15.0
> >
> > Thanks in advance,
> >
> > Faryar
> >
> > -----Original Message-----
> > From: nobody@groupstudy.com [mailto:nobody@groupstudy.com] On Behalf Of
> > ELDHO PAUL
> > Sent: Saturday, July 01, 2006 6:20 AM
> > To: Sami
> > Cc: ccielab@groupstudy.com
> > Subject: Re: Access list
> >
> > A more currect answer seems to be
> > 51.1.0.1 0.0.0.8
> > We will get the first portion 51.1.0.1 by doing an and opration of all
> > the four ip addresses and the wildcard portion by doing the XOR
> > operation of all the four ip addresses.
> >
> >
> >
> >
> >
> >
> > On 7/1/06, ELDHO PAUL <cciein2006@gmail.com> wrote:
> > >
> > > I think we can match it with 2 access lists
> > > 51.3.0.1 0.6.0.0
> > > 51.3.0.9 0.6.0.0
> > >
> > >
> > > On 7/1/06, Sami < sy1977@gmail.com> wrote:
> > > >
> > > > Group,
> > > >
> > > > One of the task say use minimum amount of line necessary to comple
> > > > this task.
> > > >
> > > > 51.3.0.1
> > > > 51.5.0.1
> > > > 51.7.0.1
> > > > 51.3.0.9
> > > > 51.5.0.9
> > > > 51.7.0.9
> > > >
> > > > How can I combine in one access list ?
> > > >
> > > > Thanks
> > > >
> > > > ____________________________________________________________________
> > > > ___ Subscription information may be found at:
> > > > http://www.groupstudy.com/list/CCIELab.html
> >
> > _______________________________________________________________________
> > Subscription information may be found at:
> > http://www.groupstudy.com/list/CCIELab.html
>
> _______________________________________________________________________
> Subscription information may be found at:
> http://www.groupstudy.com/list/CCIELab.html
>
> _______________________________________________________________________
> Subscription information may be found at:
> http://www.groupstudy.com/list/CCIELab.html
>
> _______________________________________________________________________
> Subscription information may be found at:
> http://www.groupstudy.com/list/CCIELab.html
This archive was generated by hypermail 2.1.4 : Tue Aug 01 2006 - 07:13:46 ART